cost price of article A is doubled then that of article B and shopkeeper mark up both the article 47% more than the cost price at the time of sale shopkeeper gave Rs.59 discount and earn 13 percentage profit on total .find the cost price of the article A
Answers
Answer:
let the cost price of article B be denoted as xx
then that of article A is 2x2x
If shopkeeper marks up both the articles 20% more than the cost price, then the marked price of A is;
\frac{100+20}{100}*2x=2.4x
100
100+20
∗2x=2.4x
and that of B is
\frac{100+20}{100}*x=1.2x
100
100+20
∗x=1.2x
The total price of A and B is;
2.4x+1.2x=3.6x2.4x+1.2x=3.6x
The total cost of A and B is
x+2x=3xx+2x=3x
when the shopkeeper gave Rs. 9 discount on the total , he/she sold at
3.6x-9
If this amount is equal to 117% of the cost price, then, the cost price can be computed as;
if 117%= 3.6x-9
100%=??
\begin{gathered}cost=\frac{3.6x-9}{117} *100\\=\frac{3.6x-9}{1.17}\end{gathered}
cost=
117
3.6x−9
∗100
=
1.17
3.6x−9
Equating this to the initial cost price we get;
\begin{gathered}3x=\frac{3.6x-9}{1.17}\\3.51x=3.6x-9\\3.6x-3.51x=9\\0.09x=9\\x=100\end{gathered}
3x=
1.17
3.6x−9
3.51x=3.6x−9
3.6x−3.51x=9
0.09x=9
x=100
Cost price of article A is 2x= 2*100= Rs 200