Question

cost price of one bat is 5x and that of one ball is x/2 Quantity | :profit earned on bat if he sold at price 6.2x. Quantity || : Discount % on ball if he marks up the ball by 80% of cost price and earned a profit of 3/20x​

Answer 1

Solution :-

→ CP of bat = 5x

→ SP of bat = 6.2x

→ Profit Earned = SP - CP

→ Profit = 6.2x - 5x = 1.2x .

→ Profit % = (Profit * 100)/CP

→ Profit % = (1.2x * 100)/5x = 24% . (Ans.)

_____________

→ CP of ball = (x/2)

→ Mark up % = 80%

→ Mark up Price = CP * (100 + Mark up%) / 100

→ Mark up Price = {(x/2) * 180} / 100 = 0.9x .

→ Profit = (3/20)x

→ SP = CP + Profit

→ SP = (x/2) + (3x/20) = (10x + 3x) /20 = (13x/20)

Therefore,

→ SP = Mark up Price * (100 - Discount%) / 100

Let (100 - D%) = y

→ (13x/20) = 0.9x * y / 100

→ 65x = 0.9x * y

→ y = (65/0.9)

→ y = 72.23

Hence,

→ 100 - D = 72.23

→ D = 100 - 72.23

→ D = 27.77 % (Ans.)