Chemistry, asked by jyothirmayeegovada, 11 months ago

Cost to deposit 27 grams of "Al" is Rs 3000/-. Cost to deposit 6 grams of "Mg" will be
(A) 1500/-
(B) 750/-
(C) 500/-
(D) 250/-​

Answers

Answered by SUBRATA4322
0

Answer:

CHEMISTRY

A solution is defined as a:

A .

Homogeneous mixture of two or more substances

B .

Heterogeneous mixture of two or more substances

C .

Homogeneous mixture of liquid and solid components only

D .

Homogeneous mixture consisting of water as one of the components

A solution is a homogeneous mixture of two or more substances. A solution may exist in any phase. 

A solution consists of a solute and a solvent. 

The solute is the substance that is dissolved in the solvent.

For example, in a saline solution, salt is the solute dissolved in water as the solvent.

Answered by Jasleen0599
0

Given:

The amount of aluminium deposited = 27 gm

Cost = Rs. 3000

The amount of Mg deposited = 6 gm

To Find:

The cost to deposit this amount of Mg.

Calculation:

- No of moles of Al in 27 gm = 1

- No of moles of electricity required to deposit 1 mole of Al = 3

- The cost of 1 mole of electricity = 3000/3 = Rs. 1000

- No of moles of Mg in 6 gm = 6/24 = 1/4

- No of moles of electricity required to deposit 1 mole of Mg = 2

⇒ No of moles of electricity required to deposit 1/4 mole of Mg = 2 × 1/4 = 1/2

- The cost of 1/2 mole sof electricity = 1000 × 1/2 = Rs. 500/-

- So, the cost to deposit 6 gm of Mg will be (C) Rs. 500/-.

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