Math, asked by apurbanayak248, 8 months ago

Costheta +sintheta=A and sintheta-costheta=B then prove that A²+B²=2

Answers

Answered by amansharma264

2

Answer:

please Mark as brilliant answer

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Answered by kingsleychellakkumar

2

Answer:

Proved.

Step-by-step explanation:

A²+B² = (Cosθ+Sinθ)² + (Sinθ-Cosθ)²

=Cos²θ+Sin²θ+2.Sinθ.Cosθ + Sin²θ+Cos²θ-2.Sinθ.Cosθ

2.Sinθ.Cosθ - 2.Sinθ.Cosθ = 0

Cos²θ+Sin²θ = 1

= 1+1 =2

∴A²+B² = 2.

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