Costruct the line segment of 4cm and draw a perpendicular bisector on it.
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Answers
ANSWER
1.Draw a straight line PQ=4cm
2.Using compass bisect the line PQ
Result:PA=AQ=2cm is the required perpendicular bisector.
Answer:
1.Draw a line segment AB = 4 cm.
2.Taking 4 as centre and radius more than ½ AB (i.e., 2 cm) draw an arc say it intersect AB at E.
3.Taking E as centre and with same radius as above draw an arc which intersect previous arc at F.
Again, taking F as centre and with same radius as above draw an arc which intersect previous arc (obtained in step ii) at G.
5.Taking G and F are centres, draw arcs which intersect each other at H.
6.Join AH . Thus, AX is perpendicular to AB at A. Similarly, draw BY ⊥ AB at B.
Now, we know that if two lines are parallel, then the angle between them will be 0° or
180°.
Here, ∠XAB = 90° [∴ XA ⊥ AB]
and ∠YBA = 90° [ ∴ YB ⊥ AB]
∠XAB+ ∠YBA = 90° + 90° = 180°
So, the lines XA and YS are parallel.
[since, it sum of interior angle on same side of transversal is 180°, then the two lines are
parallel]