Question

cosx=1 /root 1+tan^2x

Answer 1

Answer:

Step-by-step explanation:

RHS = $\frac{1}{\sqrt{1 + tan^{2}x } }$

        =$\frac{1}{secx}$                    [∵$sec^{2}x = 1 + tan^{2}x$

                                  ∵$secx = \sqrt{1 + tan^{2}x}$]  

        =$cosx$                                [∵$\frac{1}{secx} = cosx$]

        = LHS

Hence proved.

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