(cosx/2+sinx/2)^2=???
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Answered by
0
Answer:
(cosx/2+sinx/2)^2
(a+b)^2=a^2+b^2+2ab
(cosx/2)^2+(sinx/2)^2+2×cosx/2×sinx/2
Answered by
0
Answer:
1+ 2sin x
Step-by-step explanation:
=(cos x/2 + sin x/2)^2
=cos^2(x/2)+ sin^2(x/2) + 2sin x/2 cos x/2
= 1+ 2sin x
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