Math, asked by harshalzade3031, 10 months ago

(cosx/2+sinx/2)^2=???​

Answers

Answered by rajpreethayer80gm
0

Answer:

(cosx/2+sinx/2)^2

(a+b)^2=a^2+b^2+2ab

(cosx/2)^2+(sinx/2)^2+2×cosx/2×sinx/2

Answered by snowysecret34
0

Answer:

1+ 2sin x

Step-by-step explanation:

=(cos x/2 + sin x/2)^2

=cos^2(x/2)+ sin^2(x/2) + 2sin x/2 cos x/2

= 1+ 2sin x

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