[(cosx/2+sinx/2)^2]/[(cosx/2+sinx/2).(cosx/2-sinx/2)]
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(cosx/2+sinx/2)^2]/[(cosx/2+sinx/2).(cosx/2-sinx/2)
= (cosx/2+sinx/2)^2]/(cos^2x/2-sin^2x/2)
={cos^2 x/2+sin^2 x/2 +2sinx/2cosx/2}/cosx
=(1+sinx)/cosx
=secx+tanx ans.
= (cosx/2+sinx/2)^2]/(cos^2x/2-sin^2x/2)
={cos^2 x/2+sin^2 x/2 +2sinx/2cosx/2}/cosx
=(1+sinx)/cosx
=secx+tanx ans.
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