Question

cOSX-cos2x ÷1 - COSX=
2cosx + 1​

Answer 1

Answer:

Explanation:

We need

cos2x=2cos2x−1

Therefore,

∫(cosx−cos2x)dx1−cosx=∫(cos2x−cosx)dxcosx−1

=∫(2cos2x−1−cosx)dxcosx−1

=∫(2cosx+1)(cosx−1)dxcosx−1

=∫(2cosx+1)dx

=2sinx+x+C

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