Math, asked by TbiaSupreme, 1 year ago

cosx/cosx-1,Integrate the given function w.r.t. x considering them well defined and integrable over proper domain.

Answers

Answered by MaheswariS
0

In the attachments I have answered

this problem.


I have applied decomposition method to find the anti derivative of the given function.


In the attachment I have answered this problem.

Attachments:
Answered by hukam0685
0
Dear Student,

Answer: ∫ cosx/cosx-1 dx=
x + cot( \frac{x}{2} ) + c

Solution:

 \int{\frac{ cos \: x}{ (cos \: x- 1 )}} dx

 \int{\frac{cosx + 1 - 1}{cos \: x - 1}}

split the term like

 \int{\frac{cos \: x - 1}{cos \: x - 1}}dx +\int{\frac{1}{cos \: x - 1}} dx\\ \\ = \int {1}dx \: -\int{ \frac{1}{1 -cos \: x }} dx

as we know that

cos \: 2x = 1 - 2 {sin}^{2} x

 = \int{1}dx \: - \int{\frac{1}{2 {sin}^{2} ( \frac{x}{2}) } }dx \\ = \int{1}dx \: - \int{\frac{1}{2 } {cosec}^{2} (\frac{x}{2} ) }dx

as we know that ∫1dx = x + c

 {cosec}^{2} dx = - cot \: x + c

so apply formula

 = x + \frac{1}{2} \times ( \frac{1}{ \frac{1}{2} } )cot( \frac{x}{2} ) + c \\ \\ = x + cot (\frac{x}{2} ) + c

Hope it helps you.
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