Question

cosx-cotx/cosx.cotx=sinx-1/cosx

Answer 1

Solution:

LHS = (cosx-cotx)/(cosxcotx)

= cosx/(cosxcotx) -cotx/(coxcotx)

= 1/cotx - 1/cosx

= 1/(cosx/sinx) - 1/cosx

/*cotx = cosx/sinx */

= (sinx/cosx) - 1/cosx

= (sinx - 1)/cosx

= RHS

••••

Answer 2

hope this helps you

thanku

mark me as brainliest