Math, asked by ellipilliramalakshmi, 8 months ago

cosx reduction formula​

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Answered by Anonymous
17

Answer:

To derive the reduction formula, rewrite cosnx as cosxcosn−1x and then integrate by parts. But this gives you (n−1)∫cosnxdx somewhere on the right: In=sinxcosn−1x+(n−1)In−2−(n−1)In

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Answered by Anonymous
4

To derive the reduction formula, rewrite cosnx as cosxcosn−1x and then integrate by parts. But this gives you (n−1)∫cosnxdx somewhere on the right: In=sinxcosn−1x+(n−1)In−2−(n−1)In .

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