Math, asked by rajkr98, 9 months ago

cosxcos2xcos3x diffrentiate w.r.t x ​

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Answers

Answered by mahi1066
0

Answer:

-sinx -2sin2x -3sin3x

Answered by ranitiwari98
0

Answer:

[d/dx(cosx)cos2xcos3x]+[cosx d/dx(cos2x)cos 3x]+ [cosx cos2x d/dx(cos3x)]

=-sinx cos 2x cos 3x+cosx(-2sin2x)cos3x+cos x cos2x(-3sin3x)

=-sinx cos2x cos 3x-2cosx sin2x cos3x-3cosx cos 2xsin3x

Step-by-step explanation:

hope it helps you

mark brainliest

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