Math, asked by jahanavidubey9616474, 17 days ago

cot 0/ cosec 0+1 + cosec 0+1 /cot 0 = 2 sec 0.​

Answers

Answered by mannat391
0

Answer:

undefined

Step-by-step explanation:

because value of cot 0 os undefined

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Answered by abhijithmathew788
0

Step-by-step explanation:

LHS = cot 0 (cos ec 0 + 1) + (cos ec 0 + 1) cot 0 cot²0+ (cos ec 0 + 1)² (cos eco + 1) cot 0 cot²0+ cos ec 20+ 2 cos ec 0+1 (cos ecl + 1) cot

=

cot²0+ cos ec²0 +2 cos ec 0 + cos ec² (cos ec ∅+1) cot

2 cos ec² ∅ + 2 cos ec ∅ (cos el + 1) cot ∅

2 cos ect(cos ec + 1) (cos ece+1) cot∅

2 cos ec ∅/cot ∅

= 2 X 1 sin ∅ × sin ∅/cos∅

=2 sec ∅

=RHS

Hence, LHS = RHS

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