Math, asked by hasina53, 5 months ago

cot (15° - A) + tan(15° + A) =

a) 4cos2A/1 + 2cos2A
b) 4cos2A/1 - 2sin2A
c)4cos2A/1 + 2sin2A
d) 4cos2A/1 - 2cos2A

Answers

Answered by Anonymous

2

4cos2A/1 + 2cos2A

b) 4cos2A/1 - 2sin2A

c)4cos2A/1 + 2sin2A

d) 4cos2A/1 - 2cos2A

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