Math, asked by Jishajisha, 2 months ago

cot 15°* cot 33° *cot 45°* cot 58° * cot 75*° cot 0 evaluate the following ​

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Answered by XxitzmizzsparklexX
4

Answer:

0

Step-by-step explanation:

Re-arranging the terms, we get,

= cot 15°.cot 75°.cot 57°.cot 33°.cot 45° - cos 0°

= cot(90°-75°).cot 75°. cot(90°-33°). cot 33° - cos 0°

= tan 75° . \frac{1}{tan 75}

tan75

1

. tan 33°. \frac{1}{tan 33}

tan33

1

. cot 45° - cos 0°(∵ cot(90° - θ) = tanθ & cotθ= 1/tanθ)

tan 75° and tan 33° will get cancelled and we will remain with 1.

So, plugging int he values of cot 45° and cos0°, we get,

1(1)-1 = 1-1 = 0

hope it helps u~~~

Answered by shashiagrawalgaya
0

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