cot 15°* cot 33° *cot 45°* cot 58° * cot 75*° cot 0 evaluate the following
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Step-by-step explanation:
Re-arranging the terms, we get,
= cot 15°.cot 75°.cot 57°.cot 33°.cot 45° - cos 0°
= cot(90°-75°).cot 75°. cot(90°-33°). cot 33° - cos 0°
= tan 75° . \frac{1}{tan 75}
tan75
1
. tan 33°. \frac{1}{tan 33}
tan33
1
. cot 45° - cos 0°(∵ cot(90° - θ) = tanθ & cotθ= 1/tanθ)
tan 75° and tan 33° will get cancelled and we will remain with 1.
So, plugging int he values of cot 45° and cos0°, we get,
1(1)-1 = 1-1 = 0
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