Math, asked by emambaig786, 7 months ago

cot^2 - 1/sin^2 = 1​

Answers

Answered by vrishali810
0

Step-by-step explanation:

i dont understand,,,,.....

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Answered by avinash00317
1

Answer:-

\cot^{2}\theta - \frac{1}{\sin^{2}\theta} = -1cot

2

θ−

sin

2

θ

1

=−1

Step-by-step explanation:

\cot^{2}\theta - \frac{1}{\sin^{2}\theta} = ?cot

2

θ−

sin

2

θ

1

=?

We know that,

\cot^{2}\theta +1 = \csc^{2}\thetacot

2

θ+1=csc

2

θ

\sin \theta = \frac{1}{\csc \theta}sinθ=

cscθ

1

\csc \theta = \frac{1}{\sin\theta}cscθ=

sinθ

1

Amwer

Now,

\cot^{2}\theta - \frac{1}{\sin^{2}\theta} = \cot^{2}\theta - \csc^{2}\theta = -1cot

2

θ−

sin

2

θ

1

=cot

2

θ−csc

2

θ=−1

Attachments:
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