cot^2 - 1/sin^2 = 1
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Answered by
0
Step-by-step explanation:
i dont understand,,,,.....
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Answered by
1
Answer:-
\cot^{2}\theta - \frac{1}{\sin^{2}\theta} = -1cot
2
θ−
sin
2
θ
1
=−1
Step-by-step explanation:
\cot^{2}\theta - \frac{1}{\sin^{2}\theta} = ?cot
2
θ−
sin
2
θ
1
=?
We know that,
\cot^{2}\theta +1 = \csc^{2}\thetacot
2
θ+1=csc
2
θ
\sin \theta = \frac{1}{\csc \theta}sinθ=
cscθ
1
\csc \theta = \frac{1}{\sin\theta}cscθ=
sinθ
1
Amwer
Now,
\cot^{2}\theta - \frac{1}{\sin^{2}\theta} = \cot^{2}\theta - \csc^{2}\theta = -1cot
2
θ−
sin
2
θ
1
=cot
2
θ−csc
2
θ=−1
Attachments:
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