Math, asked by bijoysharma061, 1 month ago

cot^2 30º-2sin^2 30º -3 by 4 cosec^2 45º

Answers

Answered by jaisakthi23nov
0

Answer:

:

(i) sin 60^@ cos 30^@ + cos 60^@ sin 30^@(ii) tan 60^@ sec 30^@ - tan 30^@ cosec 60^@

Related Answer

निम्नलिखित के मान निकालिए: <br> (i) `sin 60^(@) cos 30^(@) + sin 30^(@)cos 60^(@)` <br> `(ii) 2 tan^(2) 45^(@) + cos^(2)30^(@) - sin^(2) 60^(@)` <br> (iii) `(cos 45^(@))/(sec 30^(@) + "cosec " 30^(@))`<br>` (iv) (sin 30^(@) + tan 45^(@) - "cosec " 60^(@))/(sec 30^(@) + cos 60^(@) + cot 45^(@))` <br> (v) `(5 cos^(2) 60^(@) + 4 sec^(2) 30^(@) - tan^(2) 45^(@))/(sin^(2) 30^(@) + cos^(2) 30^(@))`

Answered by s14975apratibha07847
1

Answer:

cos 30^@ + cos 60^@ sin 30^@(ii) tan 60^@ sec 30^@ - tan 30^@ cosec 60^@ ... (@) + cot 45^(@))` <br> (v) `(5 cos^(2) 60^(@) + 4 sec^(2) 30^(@) - tan^(2) ...

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