Question

Cot^2( A/2)-tan^2(A/2) divided by cotA.cosecA

Answer 1

Step-by-step explanation:

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Answer 2

4

SOLUTION:-

[cot²(A/2)-tan²(A/2)] / (cotA-cosecA)

(cotA/2+tanA/2) (cotA/2-tanA/2)

= -------------------------------------------------

( cotA.cosecA)

[2(sin²A/2+cos²A/2) / sinA] [2cosA/sinA]

= ---------------------------------------------------------

cosA/ sin²A

[2/sinA] [ 2cosA / sinA]

= ------------------------------------

cosA / sin²A

4cosA/ sin²A

= ------------------------------

cosA/sin²A

= 4

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