[cot^2/(sina-cosa)]-1 = coseca
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sinA+1/cosA+sinA-1=cosecA+cotA?
13-May-2018 · 12 answers
Can you prove Sin^2A+sin^2A×tan^2A=1+ sec^2A? ... ={cosecA+cotA-(cosec^2 A- cot^2 A)}/Dr where Dr=cotA-cosecA+1 ... cosecA+ cotA [(1-cosecA +cotA)] /(cotA-cosecA+1).
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