cot π/20cot3π/20cot5π/20cot7π/20cot9π/20=
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1
Answer:
1
Step-by-step explanation:
cot π/20cot3π/20cot5π/20cot7π/20cot9π/20
= cot π/20 . cot 3π/20 . cot 5π/20 .
cot (π/2 - 3π/20) . cot (π/2 - π/20)
= cot π/20.cot 3π/20.cot5π/20.tan 3π/20.tan π/20
= cot 5π/20 ( since "cot & tan" are reciprocal to
each other)
= cot 45° ( since π = 180° )
= 1
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