cot 25 + cot42+ cot69+ cot48+cot65= 1/√3
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Answer:
Hey mate,
here is your answer
tan(65−θ)⇒tan[90−(65−θ)]
⇒cot(25+θ)
put in equation
cot(25+θ)−cot(25+θ)=0
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