Math, asked by joeljoeljoel200512, 8 days ago

cot 25 + cot42+ cot69+ cot48+cot65= 1/√3​

Answers

Answered by Anonymous
0

Answer:

Hey mate,

here is your answer

tan(65−θ)⇒tan[90−(65−θ)]

⇒cot(25+θ)

put in equation

cot(25+θ)−cot(25+θ)=0

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