cot^2theta - cosec ^2 theta
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1
answer is 1 dear as it is a property of trigonometry
mysticd:
it is -1
it is -1 as it cosec2x- cot2x is 1 so it becomes -1
Answered by
3
Hi ,
here I used ' x ' instead of theta .
we know that
1 ) cot x = cos x / sin x
2 ) Cosec x = 1 / sin x
3) 1 - cos² x = sin² x
according to the problem given ,
cot² x - cosec² x
= ( cos x / sin x )² - ( 1 / sin x )²
= ( cos² x - 1 ) / sin² x
= [ -(1 - cos² x ) /sin² x ]
= [ - ( sin² x ) / sin² x ]
= -1
I hope this helps you.
:)
here I used ' x ' instead of theta .
we know that
1 ) cot x = cos x / sin x
2 ) Cosec x = 1 / sin x
3) 1 - cos² x = sin² x
according to the problem given ,
cot² x - cosec² x
= ( cos x / sin x )² - ( 1 / sin x )²
= ( cos² x - 1 ) / sin² x
= [ -(1 - cos² x ) /sin² x ]
= [ - ( sin² x ) / sin² x ]
= -1
I hope this helps you.
:)
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