Cot^2x- cos^2x=cos^4x cosec^2x
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Answered by
1
ANSWER:-
Take LHS and change to cosines an sines and then rearrange to arrive at the RHS
=cos2xsin2x−cos2x
=cos2x−cos2xsin2xsin2x
factorise numerator
=cos2x(1−sin2x)sin2x
⇒cos2x⋅cos2xsin2x
=cos2x⋅(cos2xsin2x)
=cos2xcot2x=cot2xcos2x
LHS=RHS
PLEASE MARK AS BRAINLIEST
Take LHS and change to cosines an sines and then rearrange to arrive at the RHS
=cos2xsin2x−cos2x
=cos2x−cos2xsin2xsin2x
factorise numerator
=cos2x(1−sin2x)sin2x
⇒cos2x⋅cos2xsin2x
=cos2x⋅(cos2xsin2x)
=cos2xcot2x=cot2xcos2x
LHS=RHS
PLEASE MARK AS BRAINLIEST
Answered by
5
cot2x-cos2x=cos4xcosec2x
lhs=cos2x/sin2x-cos2x
= cos2x-sin2xcos2x/sin2x
=cos2x(1-sin2x)/sin2x
=cos2xcos2x/sin2x
=cos4x/sin2x
=cos4x cosec2x
hence proved
lhs=rhs
And PLEASE MARK ME AS A BRAINLIST I NEED ONLY ONE THAT U CAN GIVE ME SO PLEASE
for better understanding watch the attachment
lhs=cos2x/sin2x-cos2x
= cos2x-sin2xcos2x/sin2x
=cos2x(1-sin2x)/sin2x
=cos2xcos2x/sin2x
=cos4x/sin2x
=cos4x cosec2x
hence proved
lhs=rhs
And PLEASE MARK ME AS A BRAINLIST I NEED ONLY ONE THAT U CAN GIVE ME SO PLEASE
for better understanding watch the attachment
Attachments:
horrorhunter:
thanks for marking me as brainlist
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