Question

cot 30 degree upon sec 30 degree + cosec 30 degree upon tan 45 degree minus 2 cos 0 degree upon sin 30 degree + cos square 45 degree​

Answer 1

Answer:

0

Step-by-step explanation:

Tan45/Cosec30 + Sec60/Cot45 - 5Sin90/2Cos0

Tan45 = Cot 45 = 1;

Sin30 = Cos60 = 1/2 => Cosec30 = Sec60 = 2.

Sin90 = Cos0 = 1.

= 1 /2 + 2 / 1    - 5(1) / 2(1)

= 1/2 + 2 - 5/2

= 5/2 - 5/2

= 0

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Answer 2

The value of $\dfrac{\cot30^{\circ}}{\sec30^{\circ}}+\dfrac{\csc 30^{\circ}}{\tan45^{\circ}} -\dfrac{2\cos0^{\circ}}{\sin30^{\circ}}+\cos^245^{\circ}$ is 0.

Step-by-step explanation:

In this case, we need to find the value of following trigonometric values:

$\dfrac{\cot30^{\circ}}{\sec30^{\circ}}+\dfrac{\csc 30^{\circ}}{\tan45^{\circ}} -\dfrac{2\cos0^{\circ}}{\sin30^{\circ}}+\cos^245^{\circ}$

For this we must know the values of above trigonometric value. It will become:

$\dfrac{\cot30^{\circ}}{\sec30^{\circ}}+\dfrac{\csc 30^{\circ}}{\tan45^{\circ}} -\dfrac{2\cos0^{\circ}}{\sin30^{\circ}}+\cos^245^{\circ}\\\\=\dfrac{\sqrt{3}}{(2/\sqrt{3})}+\dfrac{2}{1} -\dfrac{2(1)}{(1/2)}+(1/\sqrt2)^2\\\\=\dfrac{3}{2}+2-4+\dfrac{1}{2}\\\\=0$

So, the value of $\dfrac{\cot30^{\circ}}{\sec30^{\circ}}+\dfrac{\csc 30^{\circ}}{\tan45^{\circ}} -\dfrac{2\cos0^{\circ}}{\sin30^{\circ}}+\cos^245^{\circ}$ is 0. Hence, this is the required solution.

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Trigonometry

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