(cot 30/sec 30) + (cosec 30/tan 45) - (2cos 0/sin 30) + cos^245. Pls its urgent
Answers
Answered by
2
Answer:
(cot 30/sec 30) + (cosec 30/tan 45) - (2cos 0/sin 30) + cos^245.
= (√3/ 2/√3) + (2/1) - (2*1/ 1/2) + (1/√2)2
= 3/2 + 2 - 4 + 1/2
= (3/2 + 1/2) - 2
= (4/2) - 2
= 2 - 2
=0
Answered by
7
HEY MATE YOUR ANSWER IS HERE....
★SOLUTION ( BY USING TRIGNOMATRIC VALUES)★
★ VALUES TO BE USED ★ :-
★ ANSWER ★
THANKS FOR UR QUESTION HOPE IT HELPS..
★ KEEP SMILING ☺️✌️ ★
Similar questions
India Languages,
5 months ago
Math,
11 months ago
English,
11 months ago
Chemistry,
1 year ago
French,
1 year ago