Question

Cot 30 upon sec 30 + cosec 30 upon tan 45 - 2 cos 0 upon sin 30 + cos square 45

Answer 1

Answer:

answer o

refer to attach image for answer

Answer 2

The value of $\dfrac{\cot 30}{\sec 30} +\dfrac{\csc 30}{\tan 45}-2\dfrac{\cos 0}{\sin 30} +\cos^2 45$ is equal to zero(0).

Step-by-step explanation:

We have,

$\dfrac{\cot 30}{\sec 30} +\dfrac{\csc 30}{\tan 45}-2\dfrac{\cos 0}{\sin 30} +\cos^2 45$

To find, the value of $\dfrac{\cot 30}{\sec 30} +\dfrac{\csc 30}{\tan 45}-2\dfrac{\cos 0}{\sin 30} +\cos^2 45$ = ?

∴ $\dfrac{\cot 30}{\sec 30} +\dfrac{\csc 30}{\tan 45}-2\dfrac{\cos 0}{\sin 30} +\cos^2 45$

$=\dfrac{\sqrt{3}}{\dfrac{2}{\sqrt{3}} } +\dfrac{2}{1}-2\dfrac{1}{\dfrac{1}{2}} +(\dfrac{1}{\sqrt{2}})^2$

$= \dfrac{3}{2} +\dfrac{2}{1}-4+\dfrac{1}{2}$

$= (\dfrac{3}{2} +\dfrac{2}{1}+\dfrac{1}{2})-4$

$= \dfrac{3+4+1}{2}-4$

$= \dfrac{8}{2}-4$

= 4 - 4

= 0

The value of $\dfrac{\cot 30}{\sec 30} +\dfrac{\csc 30}{\tan 45}-2\dfrac{\cos 0}{\sin 30} +\cos^2 45$ = 0

Thus, the value of $\dfrac{\cot 30}{\sec 30} +\dfrac{\csc 30}{\tan 45}-2\dfrac{\cos 0}{\sin 30} +\cos^2 45$ is equal to zero(0).