cot^(4)a-1=csc^(4)a-2 csc^(2)a
Answers
Answered by
1
Step-by-step explanation:
It is
Write
csc
4
x
as
1
sin
4
x
and
cot
4
x
as
cos
4
x
sin
4
x
⇒
csc
4
x
−
cot
4
x
=
1
sin
4
x
−
cos
4
x
sin
4
x
=
1
−
cos
4
x
sin
4
x
Now recall that
a
2
−
b
2
=
(
a
−
b
)
⋅
(
a
+
b
)
and use this fact with
a
2
being and
b
2
being
cos
4
x
so that
a
is 1 and b is
cos
2
x
So
csc
4
x
−
cot
4
x
=
1
−
cos
4
x
sin
4
x
=
(
1
−
cos
2
x
)
⋅
1
+
cos
2
x
sin
4
x
But
cos
2
x
+
sin
2
x
=
1
so that
1
−
cos
2
x
=
sin
2
x
so
csc
4
x
−
cot
4
x
=
sin
2
x
⋅
1
+
cos
2
x
sin
4
x
=
1
+
cos
2
x
sin
2
x
=
(
1
sin
2
x
)
+
(
cos
2
x
sin
2
x
)
=
c
s
x
2
x
+
cos
2
x
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