cot 40 degree by tan 50 degree minus 1 by 2 (cos 35 degree by sin 55 degree )
Answers
Answered by
11
cot 40 / tan 50 - 1/2 ( cos 35 / sin 55 )
= tan 50 / tan 50 - 1/2 ( sin 55 / sin 55 )
= 1 - 1/2
= 1/2
= tan 50 / tan 50 - 1/2 ( sin 55 / sin 55 )
= 1 - 1/2
= 1/2
Answered by
4
Given:
cot 40 degree by tan 50 degree minus 1 by 2 (cos 35 degree by sin 55 degree ).
To Find:
The value of the given expression.
Solution:
1) We will write the given term in the mathematical term
cot 40°/tan 50°- 1/2 (cos 35°/sin 55°)
2) To solve this question we will use the property of the trigonometry.
- tan(90-∅) = cot∅
- sin(90-∅) = cos∅
3)cot 40°/tan 50°- 1/2 (cos 35°/sin (55°)
- cot 40°/tan (90°-50°)- 1/2 (cos 35°/sin (90°-35°)
- cot 40°/tan 40°- 1/2 (cos 35°/cos 35°)
- 1 -1/2
- 1/2
cot 40°/tan 50°- 1/2 (cos 35°/sin 55°) = 1/2
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