Question

Cot(45°-A)=tan 2A + sec 2A​

Answer 1

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Question :-

Prove Cot(45°-A)=tan 2A + sec 2A

Answer :-

R.H.S.

= 1 / cos(2a) + sin(2a) / cos(2a)

= (1 + sin(2a)) / (cos(2a))

= (sin^2(a) + cos^2(a) + 2 × sin(a) × cos(a)) / (cos^2(a) - sin^2(a))

= (sin(a) + cos(a))^2 / ((cos(a) - sin(a)) * (cos(a) + sin(a)))

= (cos(a) + sin(a)) / (cos(a) - sin(a))

= cos(a) × (1 + sin(a) / cos(a)) / (cos(a) × (1 - sin(a)/cos(a)))

= (1 + tan(a)) / (1 - tan(a))

= (tan(45) + tan(a)) / (1 - tan(a) * tan(45))

= tan(a + 45)

Answer 2

Answer:

Refer to the attachment

Step-by-step explanation:

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