Math, asked by aashuchy2, 1 year ago


cot (45° + A) + tan (45º – 2A)=2cos2A/1-sin2A​

Answers

Answered by thandra1982
0

Answer:

Answer:tan(45-A)+cot(45+A)=\ frac{2cos2A}{1+sin2A}Step-by-step explanation: Formula ... =2\frac{cos2A}{cos^2A+sin^2A+.

Answered by PriyanshSingla
0

Answer:

tan(45-A)+cot(45+A)=\ frac{2cos2A}{1+sin2A}tan(45−A)+cot(45+A)= frac2cos2A1+sin2A Step-by-step explanation: Formula ... =2\frac{cos2A}{cos^2A+sin^2A+.

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