Question

cot 54° + tan 20°
—————————
tan 36° + cot 70°




Divide
tell the answer.​

Answer 1

Answer:

(cot54+tan20)÷(tan36+cot 70)= {cot (90-36)+tan (90-70)}÷tan36 +cot 70

= (tan 36+ cot 70)÷(tan 36+cot 70)=1

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Answer 2

Answer:

Correct Question:

${ \sf{ \frac{cot54°}{tan36°} + \frac{tan20°}{cot70°} =? }}$

Solution:

${ \implies{ \sf{ \frac{cot54°}{tan36°} + \frac{tan20°}{cot70°} }}}$

${ \implies{ \sf{ \frac{cot(90 - 36)}{tan36°} + \frac{tan(90 - 70)}{cot70°} }}}$

${ \implies{ \sf{ \frac{tan36°}{tan36°} + \frac{cot70°}{cot70°} }}}$

${ \implies{ \sf{ \cancel{{ \frac{tan36°}{tan36°}}} + { \cancel{\frac{cot70°}{cot70°} }}}}}$

${ \implies{ \sf{1 + 1}}}$

${ \implies{ \sf{2}}}$

${ \mathbb{ \pmb{ \blue{LEARN \: MORE...!! }}}}$

• Sin ( 90 - θ) = Cosθ

• Tan(90 - θ) = Cotθ

• Csc(90 - θ) = Secθ