(cot 6+3) (3 cot 0+1) = 3 cosec 0 +10 cot 6
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Evaluate:
cot
−1
3
1
−cosec
−1
(−2)+sec
−1
(
3
2
)
Hard
Solution
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Given, cot
−1
3
1
−cosec
−1
(−2)+sec
−1
(
3
2
)
Let x=cot
−1
3
1
=
2
π
−tan
−1
3
1
We know that range of tan
−1
is (
2
−π
,
2
π
)
=
2
π
−
6
π
=
6
3π−π
=
6
2π
=
3
π
∴x=
3
π
Let y=cosec
−1
(−2)
since cosec
−1
x=sin
−1
x
1
⇒y=sin
−1
(
2
−1
)
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