Math, asked by tenthpp, 5 days ago

cot(90-a)/cosec^2 A . secA.cot^3A/sin^2(90-A)= root of (tan^2A+1)

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Answered by 919438089392

1

Answer:

cot(90-A)/tanA + cosec(90-A) sinA/tan(90-A) tanA/tanA + secA.sinA/cotA 1 + sin^2A/cos^2A cos^2A + sin^2A/ cos^2A 1/cos^2A sec^2A.

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