Question

cot (90-A) +cosec (90-A) =1+sinA/cos A​

Answer 1

Step-by-step explanation:

Trigonometry Identity

• cot(90-A) = tanA
• cosec(90-A) = secA
• tanA=sinA/cosA
• cosecA=1/sinA

LHS :

cot(90-A) + cosec(90-A)

tanA+secA

tanA+secAsinA/cosA+1/cosA

tanA+secAsinA/cosA+1/cosA(sinA+1)/cosA

RHS

(sinA+1)/cosA

Since LHS=RHS

Hence Proved