Math, asked by mkyashasraj, 4 months ago

cot (90°- theta)tan theta-cosec (90°-theta)sec theta /
sin12°cos 15° sec78° cosec75° +cos^2 (50° +theta)+cos^2(40- theta)/ tan15º tan37° tan53° tan75°

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Answered by Krishrkpmlakv

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