Question

Cot A/2+tanA/2=2cosec A
please verify it
I will mark it as brainliest
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Answer 1

Answer:

tanA/2+ cotA/2=

sin(A/2)/cos(A/2)+ cos(A/2)/sin(A/2)=

[sin^2(A/2)+cos^2(A/2)]/sin(A/2)cos(A/2)=

1/[1/2sin2A/2]=2/sinA=2cosecA

1/(cosA+sinA)+1/(cosA-sinA)=

(cosA-sinA+cosA+sinA)/(cosA+sinA)(cosA-sinA)=

2cosA/[cos^2(A)-sin^2(A)]=

2cosA/cos2A=

2cosA*sin2A/cos2A*sin2A=

tan2A*2cosA/sin2A=

tan2A* 2cosA/2sinAcosA=

tan2A/sinA=

tan2A*1/sinA=

tan2A*cosecA