Question

Cot A =4/3 find all other sides using Pythagoras theroam.
class X maths chapter 8​

Answer 1

Given: COT(A) = 4/3 = b/p

So we got h = √b²+p² = √4²+3² = √16+9 = √25 = 5

So: SIN(A) = p/h = 3/5

So: COS(A) = b/h = 4/5

So: TAN(A) = p/b = 3/4

So: COSSEC(A) = h/p = 5/3

So: SEC(A) = h/b = 5/4

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Answer 2

Answer: All three sides are base=4 , height = 3 , hypotenuse= 5

cot A = 4/3 = base/height

base=4 , height = 3

using Pythagoras theorem to find hypotenuse

hypotenuse = √ 4^2 + 3^2

hypotenuse = √ 16 + 9

 hypotenuse = √25 = 5  

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