Cot(a+b)=0and sin(a+2b)=?
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If cot (a+b) = 0 = cot (π/2), then : a+b = π/2.
∴ sin ( a + 2b ) = sin [ (a+b) + b ] = sin [ (π/2) + b ] = cos b ... Ans.
∴ sin ( a + 2b ) = sin [ (a+b) + b ] = sin [ (π/2) + b ] = cos b ... Ans.
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