Math, asked by joe59, 11 months ago

cot (A+B)=cotAcotB-1/cotA+cotB​

Answers

Answered by Davezac
4

Answer:

RS = ((cosA/sinA)(cosB/sinB) -1)/(cosA/sinA + cosB/sinB)

= (cosAcosB/(sinAsinB)-sinAsinB/(sinAsinB)/(sinBcosA + cosBsinA)/(sinAsinB))

= (cosAcosB-sinAsinB)/(sinAsinB)*(sinAsinB)/(sinBcosA + cosBsinA)

= cos(A+B)/sin(A+B)

= cot(A+b)

LHS=RHS, Hence proven

Answered by aayusharadhi45
0

Answer:

Step-by-step explanation:

RS = ((cosA/sinA)(cosB/sinB) -1)/(cosA/sinA + cosB/sinB)

= (cosAcosB/(sinAsinB)-sinAsinB/(sinAsinB)/(sinBcosA + cosBsinA)/(sinAsinB))

= (cosAcosB-sinAsinB)/(sinAsinB)*(sinAsinB)/(sinBcosA + cosBsinA)

= cos(A+B)/sin(A+B)

= cot(A+b)

LHS=RHS, Hence proven

Similar questions