Question

cot A-cosA
cot A+cos A
cosec A-1
cosec A +1​

Answer 1

Answer:

cos a/sina -sina

cos/sina -sina

Answer 2

Correct Question :-- (cot A-cosA)/(cot A+cos A) = (cosec A-1) / (cosec A +1)

Formula used :-

• CotA = cosA/sinA
• cosecA = 1/sinA

Solution :--

Solving the LHS part first, by putting cotA = cosA/sinA , we get,

→ (cotA - cosA) / (cotA+cosA)

→ [(cosA/sinA) - cosA ] / [(cosA/sinA) + cosA ]

Taking cosA common From Numerator and denominator now,

→ cosA [(1/sinA) - 1] / cosA[(1/sinA) + 1 ]

cosA will be cancel now,

→ [(1/sinA) -1] / [(1/sinA) + 1 ]

Putting (1/sinA) = cosecA now,

→ (cosecA - 1) / (cosecA + 1) = ❁❁ RHS ❁❁

✪✪ Hence Proved ✪✪