Math, asked by pranavkutar14, 11 months ago

cot A cot 2A - cot 2A cot 3A - cot 3A cot A = 1​

Answers

Answered by Anonymous
19

Answer:

L.H.S. = cot A cot 2A – cot 2A cot 3A – cot 3A cot A

= cot A cot 2A – cot 3A (cot 2A + cot A)

= cot A cot 2A – cot (2A + A) (cot 2A + cot A)

= cotA cot2A - [ (cot2A cotA - 1) / (cotA + cot2A) ] (cot2A + cotA)

[ Since cot(A+B) = (cotA cotB - 1) / (cotA + cotB) ]

= cot A cot 2A – (cot 2A cot A – 1)

= 1 = R.H.S.

Hope it will help you.⚡

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