Question

Cot A tan(90-A)- sec(90-A)cosecA+(sin²25 +sin²65) +root 3 (tan 5 tan 15 tan 30 tan 75 tan 85)

Answer 1

CotA.tan(90°-A)-sec(90°-A)coseca+(sin²35°+sin²55°) +√3(tan5°.tan15°.tan30°.tan75°.tan85°)

=cotA.cotA-cosecA.cosecA+sin²35°+sin²(90°-35°)+√3{tan5°.tan15°.(1/√3).
tan(90°-15°).tan(90°-5°)}
=cot²A-cosec²A+sin²35°+cos²35°+√3×1/√3(tan5°tan15°cot15°cot5°)
=-1+1+{tan5°tan15°(1/tan15°)(1/tan5°)}
=1

Answer 2

Answer:

Hello my friend here is the answer.

Step-by-step explanation:

CotA.tan(90°-A)-sec(90°-A)coseca+(sin²35°+sin²55°) +√3(tan5°.tan15°.tan30°.tan75°.tan85°)

=cotA.cotA-cosecA.cosecA+sin²35°+sin²(90°-35°)+√3{tan5°.tan15°.(1/√3).

tan(90°-15°).tan(90°-5°)}

=cot²A-cosec²A+sin²35°+cos²35°+√3×1/√3(tan5°tan15°cot15°cot5°)

=-1+1+{tan5°tan15°(1/tan15°)(1/tan5°)}

=1

Hole this helps !!!!!