cot A -tan A= 2 cos^2 A -1/sin A .cos A
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Answer:
Taking LHS=cot
2
θ−cos
2
θ=
sin
2
θ
cos
2
θ
−cos
2
θ[∵cotθ=
sinθ
cosθ
]
=
sin
2
θ
cos
2
θ−sin
2
θcos
2
θ
=
sin
2
θ
cos
2
θ(1−sin
2
θ)
[∵cos
2
θ+sin
2
θ=1]
=
sin
2
θ
cos
2
θcos
2
θ
=cot
2
θcos
2
θ=RHS
Step-by-step explanation:
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