cot a + tan a = cosec a sec a
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sinA/cosA +cos A/sin A
on taking LCM
(Sin²A+cos²A)/sinA cos A
As we know sin²A+cos²A=1
1/sinA cosA⇒cosecA secA {1/cosA=secA, 1/sinA=cosecA}
Hence proved.........................
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sinA/cosA +cos A/sin A
on taking LCM
(Sin²A+cos²A)/sinA cos A
As we know sin²A+cos²A=1
1/sinA cosA⇒cosecA secA {1/cosA=secA, 1/sinA=cosecA}
Hence proved.........................
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