cot a - tan a = sec a. cosec a
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Answer:
Hi
Step-by-step explanation
We have to prove that cotA-tanA=secA.cosecA
By taking L.H.S we can prove that
(cotA-tanA)
By squaring,
(cotA-tanA)² here it looks like (a-b)²we know that
(a-b)²=a²+b²+2ab
here,a=cotA and b=tanA,let us substitute
(cotA-tanA)²=cot²A+tan²A-2(cotA)(tanA)
=cosec²A-1+sec²A-1-2(cotA)(tanA)[∵by using the identities cot²A=cosec²-1 and tan²A=sec²A-1]
=cosec²A.sec²A+2-2(cotA)(tanA)[∵I have added both -1 and -1=+2 I have got]
=cosec²A.sec²A.cotA.tanA[I have cancelled both +2 and -2]
=cosec²A.sec²A.1[∵because cotA reciprocal is tanA and tanA reciprocal is cotA so they are side by side then we can write it as 1]
=cosec²A.sec²A
∴cosecA.secA or secA.cosecA=secA.cosecA
∴L.H.S=R.H.S
∴Hence proved
Please mark it as brainlist answer
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