cot B =5/4 show that cosec^2 B= 1+cot^2 B
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8
since,
cot B =5/4 = B/P
B = 5 , P = 4
BY Pythagoras theorem,
H = √B² +P²
= √5²+4²
= √25+16
= √41
Now put the value of cos x squared theta and cot squared theta in the equation
cot B =5/4 = B/P
B = 5 , P = 4
BY Pythagoras theorem,
H = √B² +P²
= √5²+4²
= √25+16
= √41
Now put the value of cos x squared theta and cot squared theta in the equation
Unknown111111:
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1
Answer:
Step-by-step explanation:
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