Question

cot inverse a^2 - 6x^2 / 5ax

Answer 1

Answer:

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Answer 2

cot inverse a^2 - 6x^2 / 5ax:

Explanation:

• cot-1((a2 - 6x2)/(5ax))

• Let y = cot-1((a²-6x²)/5ax) = tan-1(5ax/(a²-6x²)
• ⇒tan-1(3x/a) +tan-1(2x/a)
• Differentiating with respect to x
• by solving step by step, we get

• 3a/(a²+9x²) + 2a/(a²+2x²)