Math, asked by vartikajha, 11 months ago

cot square 30 degree minus 2 cos square 60 degree ,-3 upon 4 x square 45 - 4 sin square 30​

Answers

Answered by nikitachoudhary2019
5

Here is the Answer:

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Answered by erinna
0

The value of given expression is -\dfrac{1}{14}.

Step-by-step explanation:

Note: The given expression is not correct.

Consider the given expression is

\dfrac{\cot^2 30-2\cos^2 60-3}{4\sec^245-4\sin^2 30}

From the table of trigonometry

\cot 30=\sqrt{3}, \cos 60=\frac{1}{2}, \sec 45=\sqrt{2},\sin 30=\frac{1}{2}

Substitute these values in the above expression.

\dfrac{(\sqrt{3})^2-2(\frac{1}{2})^2-3}{4(\sqrt{2})^2-4(\frac{1}{2})^2}

\dfrac{3-2(\frac{1}{4})-3}{4(2)-4(\frac{1}{4})}

\dfrac{-\frac{1}{2}}{8-1}

\dfrac{-\frac{1}{2}}{7}

-\dfrac{1}{14}

Therefore, the value of given expression is -\dfrac{1}{14}.

#Learn more

Cot square 30 degree subtract 2 cos square 60 degree minus 3 upon 4 sec square 45 degree minus 4 sec square 30 degree​.

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