Math, asked by aditya2802006, 5 months ago

cot square 30 degree subtract 2 cos square 60 degree minus 3 upon 4 sec square 45 degree minus 4 cosec square 30 degree

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Answered by pradeepjugtwan

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Answer:

[tex] cot {?}^{2} (30) \div 2 \cos {?}^{2} (60) - 3 \div 4 \sec^{2} 45 - 4 \csc {?}^{2} (30) = 3 \div 3 - 3 - 3 = 1-6= -5

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